# Line slope calculator 3x-5y=-10

**Straight line given by points A[0; 2] and B[5; 5]**

## Calculation:

**Slope-intercept form of line:**y = 0.6x+2

**Canonical form of the line equation:**3x-5y+10 = 0

**Parametric form of the line equation:**

x = 5t

y = 3t+2 ; t ∈ R

**Slope:**m = 0.6

**Slope angle of line: φ =**30°57'50″ = 0.5404 rad

**X intercept:**x

_{0}= -3.3333

**Y intercept:**y

_{0}= q = 2

**Distance line from the origin:**d

_{0}= 1.715

**The length of the segment AB: |AB| =**5.831

**Vector: AB =**(5; 3)

**Normal vector: n =**(3; -5)

**Midpoint of the segment AB: M =**[2.5; 3.5]

**Perpendicular Bisector equation:**5x+3y-23 = 0

**Vector OA = (0; 2) ; |OA| = 2**

**Vector OB = (5; 5) ; |OB| = 7.0711**

**Scalar product OA .OB = 10**

**Angle ∠ AOB = 45° = 0.7854 rad**